As raízes de x2-6x+9=0 são?
Soluções para a tarefa
Respondido por
1
x² - 6x + 9 = 0
Δ = 36 - 36
Δ = 0
x = 6 +-√0/2
x = 6+-0/2
x' = 6+0/2
x' = 6/2
x' = 3
x'' = 6-0/2
x'' = 6/2
x'' = 3 S = { 3 } ok
Δ = 36 - 36
Δ = 0
x = 6 +-√0/2
x = 6+-0/2
x' = 6+0/2
x' = 6/2
x' = 3
x'' = 6-0/2
x'' = 6/2
x'' = 3 S = { 3 } ok
ayllalaia:
Obrigado
Respondido por
0
x²-6x+9=0
a=1, b=-6, c=9
delta=b²-4.a.c
delta= -6²-4.1.9
delta= 36-36
delta= 0
x=-b±√delta/2.a
x=6±√0/2.1
x= 6+0/2= 6/2= 3
x= 6-0/2= 6/2= 3
s={3}
a=1, b=-6, c=9
delta=b²-4.a.c
delta= -6²-4.1.9
delta= 36-36
delta= 0
x=-b±√delta/2.a
x=6±√0/2.1
x= 6+0/2= 6/2= 3
x= 6-0/2= 6/2= 3
s={3}
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