Question

As raízes da equação x²+ x - 6=0 são:

Answer 1

Resposta:

Olá,

• Encontre o valor do discriminante (∆):

$\mathsf{\purple{x + x - 6 = 0}} \\ \\ \mathsf{\orange{\Delta = \ {b}^{2} - 4ac}} \\ \mathsf{\orange{\Delta = {1}^{2} - 4 \times 1 \times ( - 6)}} \\ \mathsf{\orange{\Delta = 1 - 4 \times ( - 6)}} \\ \mathsf{\orange{\Delta = 1 - ( - 24)}} \\ \mathsf{\orange{\Delta = 25}}$

• Descubra o valor de x' e x":

$\mathsf{\blue{x = \dfrac{ -b \pm \sqrt{\Delta}}{2a}}} \\ \\ \mathsf{\blue{x = \dfrac{ -1 \pm \sqrt{25}}{2 \times 1}}} \\ \\ \mathsf{\blue{x = \dfrac{ -1 \pm \: 5}{2}}}$

$\mathsf{\red{x = \dfrac{ -1 + 5}{2}}} \\ \\ {\mathsf{\red{x = \dfrac{4}{2}}}} \\ \\ \mathsf{ \red{x = 2}}$

$\mathsf{ \green{x = \dfrac{ -1 - 5}{2}}} \\ \\ \mathsf{ \green{x = \dfrac{-6}{2}}} \\ \\ \mathsf{ \green{x = -3}}$

Ω | Ass: Fallen Angel | Ω

Dúvidas comente:

Espero ter ajudado!

Answer 2

$\mathsf{\red{Vamos~fazer!!!}}$

$\boxed{\begin{array}{lr}a = \blue{ 1} \\ \\ b = \blue{1} \\ \\ c = \blue{ - 6}\end{array}}$

Com isso iremos trocar e fazer o cálculo:

$\boxed{\begin{array}{lr} \green{ {x }^{2} + x - 6 = 0 } \\ \\ Δ = {b}^{2} - 4ac \\ \\ Δ = 1 + 24 \\ \\ Δ = \red{25}\end{array}}$

Descobrindo o delta iremos descobrir agora o valor de x:

$\boxed{\begin{array}{lr}x = \gray{ \frac{ - b~~ \pm~~ \sqrt{Δ} }{2a} } \\ \\ x = \frac{ - 1~ \pm~5~~}{2} \end{array}}$

Com isso descobrirmos que:

$x = \purple{2~~} \mathsf{ou} \purple{~~ - 3}$

$\mathsf{\pink{Aprenda~mais~em:}}$

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$\boxed{\begin{array}{lr}\green{\infty}\mathbf{ \:By: ASWhiter}\end{array}}$

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$\Huge{\mathbb{\blue{Espero~ter~ajudado!!!}}}$