Question

as raízes da equação X² -7x+12=0

Answer 1

$x^{2} -7x+12=0\\\\ a=1;b=-7;c=12\\\\\\ \Delta= b^{2} -4ac\to \Delta= (-7)^{2} -4*1*12\to \Delta= 49-48\to \Delta=1\\\\\\ x=\frac{-b+- \sqrt{\Delta} }{2a} \to x=\frac{-(-7)+- \sqrt{1} }{2*1} \to x=\frac{7+- 1 }{2} \\\\\\ x'=\frac{7+ 1 }{2} \to x'=\frac{8 }{2} \to x'=4\\\\\\ x''=\frac{7-1 }{2} \to x''=\frac{6 }{2} \to x''=3\\ \\\\\\S=(3,4)$