Question

as raizes da equação x²-5x +6=0 sao dois numeros

Answer 1

$x^2-5x +6=0\\\\a=1;b=-5;c=6\\\\ \Delta=b^2-4ac\to \Delta=(-5)^2-4*1*6\to \Delta=25-24\to \Delta=1\\\\ x= \frac{-b+- \sqrt{\Delta} }{2a} \to x= \frac{-(-5)+- \sqrt{1} }{2*1} \to x= \frac{5+- 1 }{2} \to \\\\ x'= \frac{5+ 1 }{2} \to x'= \frac{6 }{2} \to x'=3\\\\ x''= \frac{5- 1 }{2} \to x''= \frac{4 }{2} \to x''=2\\\\\\ S=(2;3)$