Question

as raízes da equação 2xquadrado  -10-8x

Answer 1

$2 x^{2} -10-8x \\ \\ \Delta = (-8)^2 - 4.2.(-10) \\ \Delta = 144 \\ \\ x = \frac{-(-8) \pm \sqrt{144} }{2.2} = \frac{8 \pm 12}{4} \\ \\ x' = \frac{8+12}{4} = 5 \\ \\ x'' = -1 \\ \\ \boxed{S =\{-1;5\}}$

Answer 2

2x² - 10 - 8x = 0
2x² - 8x - 10 = 0
Δ = b² - 4 . a . c
Δ = (- 8)² - 4 . 2 . (- 10)
Δ = 64 + 80
Δ = 144

x = (- b ± √Δ)/(2 . a)
x = (- (- 8) ± √144)/(2 . 2)
x = (8 ± 12)/4

x' = (8 + 12)/4
x' = 20/4
x' = 5

x'' = (8 - 12)/4
x'' = - 4/4
x'' = - 1

S = {- 1, 5}