Question

as raízes da equação 2x²-10-8x=0 são:

Answer 1

$2x^2-10-8x=0\\x^2-4x-5=0\\\Delta=b^2-4ac=16-4.1.(-5)=16+20=36\\x=\frac{-b \pm \sqrt{\Delta} }{2a}\\\\\boxed{x'=\frac{4+6} {2}=5}\\\\\\\boxed{x''=\frac{4-6}{2}=-1}$