Question

As medidas de dois angulos opostos pelo vertice sao:2x-10°/3 e 3x/2-10

Answer 1

2x - 10...........3x
_____. = _____
.....3.............2x - 10

2x - 10 (2x - 10) = 3 (3x)

4x^2 - 20x - 20x + 100 = 9x

4x^2 - 40x + 100 - 9x = 0

4x^2 - 40x - 9x + 100 = 0

4x^2 - 49x + 100 = 0

a = 4 b = - 49 c = 100

vamos usar a formula delta (D) :

D = b^2 - 4 a c

D = (-49)^2 - 4 (4)(100)

D = 2.401 - 8 (100)

D = 2.401 - 800

D = 1.601

vamos usar a formula de brasksra :

X = - b - , + \/ D
......._________
...............2a

X = - (-49) - , + \/ 1.601
.......______________
......................2 (4)

X = 49 - , + 40,01
.......___________
...................8

X1 = 49 - 40,01
........________
................8

X1 = 8,99
........____
............8

X1 = 1,113graus -->aproximadamenta 1er angulo


X2 = 49 + 40,01
.........________
.................8

X2 = 89.01
.........____
.............8

X2 = 11,12graus-->aproximadamente 2do angulo