Question

Após análise encontre o valor de X
a)
$4x {}^{2} - x = 0$
b)
$x {}^{2} - 9 \times (20 - 16) = 0$
c)
$4x {}^{2} - 36 = 0$
d)
$4x - 3 \times (2 - 2x) = x - 4$
e)
$3 \times (x - 1) + 4 x = x - 5$

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Answer 1

Resposta:

Explicação passo a passo:

4x^2 - x = 0

X.(4x -1)= 0

X = 0

4x - 1 = 0

4x = 1

X = 1/4

R.: S = {0, 1/4}

_______________

B)

x^2 - 9.(20-16)= 0

X^2 - 9.4 = 0

X^2 - 36 = 0

X^2 = 36

X = \/36

X = +/- 6

R.: S = {6, -6}

______________

C)

4x^2 - 36 = 0

4x^2 = 36

X^2 = 36/4

X^2 = 9

X = \/9

X = +/- 3

R.: S = {3, -3}

D)

4x - 3.(2-2x) = x - 4

4x - 6 + 6x = x - 4

10x - 6 = x - 4

10x - x = - 4 + 6

9x = 2

X = 2/9

E)

3.(x-1) + 4x = x - 5

3x - 3 + 4x = x - 5

7x - 3 = x - 5

7x - x = - 5 + 3

6x = - 2 (:2)

3x = - 1

X = - 1/3