Question

Aplique Bhaskara e resolva:
a) 3X ao quadrado - 7X + 4 = 0

Answer 1

$3 x^{2} -7x+4=0\\\\\\ a=3;b=-7;c=4\\\\\\ \Delta=b^2-4ac \to \Delta=(-7)^2-4*3*4\to \Delta=49-48\to \Delta=1\\\\\\ x= \frac{-b+- \sqrt{\Delta} }{2a} \to x= \frac{-(-7)+- \sqrt{1} }{2*3} \to x= \frac{7+- 1 }{6} \to \\ \\\\ x'= \frac{7+1 }{6} \to x'= \frac{8 }{6} \to x'= \frac{4 }{3} \\\\\\ x''= \frac{7-1 }{6} \to x''= \frac{6 }{6} \to x''=1\\\\\\ S=(1; \frac{4 }{3})$

Answer 2

Resposta:

OLÁ

VAMOS A SUA PERGUNTA:⇒⇒

$\sf 3x^2-7x+4=0$

$\sf a+b=-7\\\sf ab=3\times \sf 4\sf = \sf 12$

$\sf -1,-12\\-2,-6\\-3,-4$

$\sf -1-12=-13\\-2-6=-8\\-3-4=-7$

$\sf a=-4\\b=-3$

$\sf (3x^2-4x)+(-3x+4)$

$\sf x(3x-4)-(3x-4)$

$\sf (3x-4)(x-1)$

$\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \red{x=1} }}}\ \checkmark \\\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \blue{x=\frac{4}{3}=1\frac{1}{3}\approx1,333333333 }}}}\ \checkmark$←↑←↑ RESPOSTA.

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Explicação passo-a-passo:

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