Question

Aplique as propriedades da potênciação para resolver as potência:
a)2^2.2=
b)(-2)^5:(-2)^2=
c)-2^2.(-2)=
d)(0,2)^2.(0,2)^2=
e)(0,1)^3.(0,1)^2=
f)(2^3)^2=
g)(-2)^-3=
h)-2^-3=​

Answer 1

Resposta:

Explicação passo-a-passo:

a)2^2.2= > $2^{2+1} => 2^{3}$ = 8

b)(-2)^5:(-2)^2=>  $(-2)^{5-1} => (-2)^{4}$ = 16

c)-2^2.(-2)= > $-2^{2+1} => -2^{3}$ = -8

d)(0,2)^2.(0,2)^2= > $0,2^{2+1} => (0,2)^{3}$ = 0,008

e)(0,1)^3.(0,1)^2=> $0,1^{3+2} => 2=0,1^{5}$  = 0,0000164

f)(2^3)^2=  $2^{3x2} => 2^{6}$

g)(-2)^-3= > $\frac{1}{(-2)^{3} }$ => $\frac{1}{-8^{} } =>- \frac{1}{8^{} }$

h)-2^-3=> ​$\frac{1}{-2^{3} }$ => $\frac{1}{-8^{} } =>- \frac{1}{8^{} }$