Matemática, perguntado por Yunna7v7, 4 meses atrás

Aplique a relação de Pitágoras e descubra a medida desconhecida do lado de cada triângulo, considerando as medidas indicadas​

Anexos:

Soluções para a tarefa

Respondido por CyberKirito
1

\Large\boxed{\begin{array}{l}\rm a)\\\sf x^2=9^2+12^2\\\sf x^2=81+144\\\sf x^2=225\\\sf x=\sqrt{225}\\\sf x=15\end{array}}

\Large\boxed{\begin{array}{l}\rm b)\\\sf y^2+8^2=17^2\\\sf y^2+64=289\\\sf y^2=289-64\\\sf y^2=225\\\sf y=\sqrt{225}\\\sf y=15\end{array}}

\Large\boxed{\begin{array}{l}\rm c)\\\sf y^2+y^2=18^2\\\sf 2y^2=324\\\sf y^2=\dfrac{324}{2}\\\\\sf y^2=162\\\sf y=\sqrt{162}\\\sf y=\sqrt{81\cdot2}\\\sf y=9\sqrt{2}\end{array}}

\Large\boxed{\begin{array}{l}\rm d)\\\sf y^2=15^2+4^2\\\sf y^2=225+16\\\sf y^2=241\\\sf y=\sqrt{241}\end{array}}

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