Question

aplicando o teorema de Pitágoras , determine a medida X indicada em cada um dos triângulos a seguir:​

Answer 1

Oie, tudo bom?

a)

$h {}^{2} = c _{}^{2} + c {}^{2} \\ x {}^{2} = 6 {}^{2} + 8 {}^{2} \\ x {}^{2} = 36 + 64 \\ x {}^{2} = 100 \\ x = \sqrt{100} \\ \boxed{x = 10}$

b)

$h {}^{2} = c {}^{2} + c {}^{2} \\ x {}^{2} = 15 {}^{2} + 20 {}^{2} \\ x {}^{2} = 225 + 400 \\ x {}^{2} = 625 \\ x = \sqrt{625} \\ \boxed{x = 25}$

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Answer 2

Resposta:

a)

$x^2=6^2+8^2\\ \\ x^2=36+64\\ \\ x^2=100\\ \\ x=\sqrt{100} \\ \\ x=10$

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b)

$x^2=15^2+20^2\\ \\ x^2=225+400\\ \\ x^2=625\\ \\ x=\sqrt{625} \\ \\ x=25$