Question

aplicando o teorema de Pitágoras determine a medida do X ​

Answer 1

Oi!

Teorema de Pitágoras

$\boxed{a^2= b^2 +c^2}$

a)

$13^2 = 12^2 + x^2 \\\\169 = 144^2 + x^2 \\\\x^2 = 169 - 144 \\\\x^2 = 25 \\\\x = \sqrt{25} \\\\\boxed{x= 5}$

b)

$x^2 = 3^2 + 4 ^2 \\\\x^2 = 9 + 16 \\\\x^2 = 25 \\\\x = \sqrt{25}\\\\\boxed{x = 5}$

c)

$13^2 = 5^2 + x^2 \\\\169 = 25 + x^2 \\\x^2 = 169 - 25 \\\\x^2 = 144 \\\\x = \sqrt{144}\\\\\boxed{x = 12}$

Espero ter ajudado. Bons estudos!