Question

Aplicando o método da substituição,resolva os seguintes sistemas
{3×-2y=6
{×-3y=2​

Answer 1

$\Large\mathsf\displaystyle{}\begin{cases}3x - 2y = 6 \\ x - 3y = 2\end{cases} \\\\ \Large\mathsf\displaystyle{}\begin{cases}3x - 2y = 6 \\ x = 2 + 3y\end{cases} \\\\ \Large\mathsf\displaystyle{}3\left(2 + 3y\right) - 2y = 6 \\ \Large\mathsf\displaystyle{}6 + 9y - 2y = 6 \\ \Large\mathsf\displaystyle{}9y - 2y = 0 \\\Large\mathsf\displaystyle{}7y = 0 \\\Large\mathsf\displaystyle{}y = 0 \\\\ \Large\mathsf\displaystyle{}x = 2 + 3 \cdot 0 \\ \Large\mathsf\displaystyle{}x = 2 + 0 \\ \Large\mathsf\displaystyle{}x = 2 \\ \\\LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{ \left(x,y\right) =\left(2,0\right) }}}\end{gathered} }$

$\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{{ \red{Bons}} \blue{\:Estudos}}}}\end{gathered} }$

Answer 2

Resposta:

{x=2

{y=0

Explicação passo a passo:

$\left \{ {{3x-2y=6} \atop {x-3y=2}} \right. \\\\x-3y=2\\\\\bold{x=3y+2}\\\\\\\\3x-2y=6\\\\3(3y+2)-2y=6\\\\9y+6-2y=6\\\\9y-2y=6-6\\\\7y=0\\\\y=\frac{0}{7} \\\\\bold{y=0}\\\\\\\\x=3y+2\\\\x=3(0)+2\\\\x=0+2\\\\\bold{x=2}\\\\\\\\\left \{ {{x=2} \atop {y=0}} \right.$