Question

aplicando as propriedades log na base 2(x-2)+log na base 2 (x-3)=1+log(2x-7)

Answer 1

$log_2(x-2)+log_2 (x-3)=1+log_2(2x-7)\\ \\ log_2(x-2)(x-3)=log_22+log_2(2x-7)\\ \\ log_2(x-2)(x-3)=log_2(4x-14)\\ \\ (x-2)(x-3)=4x+14\\ \\ x^2-5x+6-4x+14=0\\ \\ x^2-9x+20=0\\ \\ S=\{4,5\} \ pois \ -S=4+5=9 \ \ e \ \ P=4*5=20$