Question

Aplicando as propriedades de potencia ,resolva as expressoes AJUDA PFVR

a) 5 elevado a -4 × 625
_____(sobre)_____
5-³ × 5


b) ( 2 *elevado a 7* × 2 *elevado a -5* ) -² × 32
_____________(sobre)______________
512 × 2 *elevado a -8*

Answer 1

$\frac{5^-^4 *625}{5^-^3 * 5} = \frac{ 5^{-4} *5^4}{ 5^{-3+1} } = \frac{5^0}{5^-^2} =5^0 : 5^-^2= 5^{0-(-2)} = 5^{0+2} = 5^2 = 25$

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$\frac{( 2^{7} * 2^{-5})^-^2 *~32 }{512 * 2^-^8} = \frac{(2^2) ^{-2} *~2^5}{2^9* 2^{-8} } = \frac{ 2^{-4} *2^5}{2^1} = \frac{2^1}{2^1} = 1$