Question

Aplicando a fórmula de bhaskara na função quadratica y=x²-2x-3, obtemos os valores:

Answer 1

Boa Noite !!!

Conjunto solução : s = {3, -1}

Coeficientes :

a = 1

b = - 2

c = - 3

Δ = b² - 4.a.c

Δ = (-2)² - 4.1.(-3)

Δ = 4 + 12

Δ = 16

$x = \cfrac{-b\pm\sqrt{\Delta} }{2.a} \\\\\\x = \cfrac{2\pm4}{2} \\\\\\x' = \cfrac{6}{2} \\\\\\x' = 3\\\\\\x" = \cfrac{-2}{2} \\\\\\x" = - 1$

Espero ter ajudado :-)

Att: LDC