Question

Aplicando a fórmula Cn,p= n! p!(n,p)!, Temos: A) C7,5 B)C4,4 C)C4,0 D)C0,0

Answer 1

a)

$\frac{7! }{5! } = \frac{7.6.5! }{2! 5! } = \frac{42}{2} = 21$

b)

$\frac{4! }{4! .0! } = \frac{1}{1} = 1$

c)

$\frac{4! }{4! 0! } = \frac{1}{1} = 1$

d)

$\frac{0! }{0! .0! } = 1$

Answer 2

BOM DIA!

A)

$C(7,5)=\frac{7!}{5!.(7-5)!} \\\\C(7,5)=\frac{7!}{5!.2!} \\\\C(7,5)=\frac{7.6}{2!}\\\\C(7,5)=\frac{42}{2} \\\\C(7,5)=21$

B) LEMBRE-SE QUE $0!=1$, logo $(4-4)!=1$

$C(4,4)=\frac{4!}{4!.(4-4)!} \\\\C(4,4)=\frac{4!}{4!}\\ \\C(4,4)=1$

C)

$C(4,0)=\frac{4!}{0!.(4-0)!}\\\\C(4,0)=\frac{4!}{4!}\\\\C(4,0)=1$

D)

$C(0,0)=\frac{0!}{0!.(0-0)!}\\\\C(0,0)=\frac{1}{1.0!}\\\\C(0,0)=1$

Abraços e bons estudos!