Question

aplicando a formula bhaskara 3x ao quadrado+12x+12=0

Answer 1

fórmulas:
∆=b²-4.a.c
x=-b±√∆/2.a

∆=12²-4.3.12
∆=144-144
∆=0

x1=-12+0/2.3
-12/6
x1=-2

x2=-12-0/2.3
-12/6
x2=-2

Answer 2

3 x² + 12 x + 12 = 0
Δ = b² - 4 . a.c
Δ = 12² - 4 . 3 . 12
Δ = 144 - 144
Δ = 0
há dua raízes reais e iguais
x = - b +ou- 0/2.3
x = -12 + 0/6
x´= -2
x = -12 - 0/6
x = -2
S = {-2 ; - 2}