Question

Aplicando a Forma De Bhaskara Resolva As Seguintes Equações Do 2 Grau.

a) 3x2 - 7x + 4 = 0
b) 9y2 - 12y + 4 = 0
c) 5x2 + 3x + 5 = 0

Answer 1

a) 3x^2 - 7x + 4 = 0
Delta = b^2 - 4×a×c
= ( - 7)^2 - 4 × 3 × 4
= 49 - 48
= 1
x = -b +- raiz quadrada (b^2 -4×a×c) /2×a
x = 7 +× 1/ 2×3
x1 = 7 + 1/ 6
x1 = 8/6
(podemos simplificar ÷2)
x1 = 4/3
x2 = 7 - 1/6
x2 = 6/6
x2 = 1
x1 = 4/3 e x2 = 1

b) 9y^2 - 12y + 4
= (- 12)^2 - 4×9×4
= 144 - 144
= 0
x = 12 +- raiz (0)/ 2 × 9
x = 12 + 0/ 18
x1 = x2
x = 12/18
(simplificando por 2)
x = 6/9
(simplificando por 3)
x = 2/3

c) 5x^2 + 3x + 5
= (3)^2 - 4 × 5 × 5
= 9 - 100
= - 91

Answer 2

a) ∆=(-7)^2-4.3.4
∆=49-48
∆=1

x1=b+√∆÷2.a
x1=-7+√1÷2.3
x1=-7+1÷6
x1= -1
e
x2=b-√∆÷2.a
x2=-7-√1÷2.3
x2=-7-1÷6
x2=-4/3

b)∆=(-12)^2-4.9.4
∆=144-144
∆=0

x1=-12+√0÷2.9
x1=-12/18
x1=-4/6
e
x2=-12-√0÷2.9
x2=-4/6