Question

aplica a teoria Bhaskara x²+4x-16=0​

Answer 1

Explicação passo-a-passo:

x²+4x-16=0

a=1

b=4

c=-16

∆=b²-4ac

∆=4²-4*1*-16

∆=16+64

∆=80

-b±√∆/2a

-4±√4²*5/2*1

-4±√4²√5/2

-4±4√5/2

x¹=-2+2√5

x²=-2-2√5