Question

Ao resolver a Equação dada, temos C. S = [a,b].​

Answer 1

x^(3log x) =100/x⁵

log [x^(3log x)] = log (10²/x⁵)

(3log x)]*  log (x) = log (10²/x⁵)

3*log²(x) =  log 10²- log (x⁵)

3*log²(x) =  2*log 10- 5* log (x)

3*log²(x) =  2*1- 5* log (x)

3*log²(x)  +5*log(x) -2=0

y=log(x)

3y²+5y-2=0

y'=[-5+√(25+24)]/6=(-5+7)/6=2/6=1/3

y''=[-5-√(25+24)]/6=(-5-7)/6=-12/6=-2

y=1/3=log(x)  ==>x=10^(1/3) ==>x=∛10

y=-2 =log(x) ==>x=10^(-2)=1/100

Fazendo a=1/100    e b= ∛10

a*b³ =1/100   * 10  =1/10