Question

Ao dividir o número 31 em partes inversamente proporcionais a 3, 2, e 5 encontramos respectivamente: a)6, 15 e 10 b)15, 6 e 10 c)10, 15 e 6 d)15, 19 e 6

Answer 1

$\frac{x + y + z}{ \frac{1}{3} + \frac{1}{2} + \frac{1}{5} } = \frac{31}{\frac{1}{3} + \frac{1}{2} + \frac{1}{5} } = \frac{31}{ \frac{31}{30} } = 30\\\\ \frac{x}{ \frac{1}{3} } = 30 \\\\x = \frac{1}{3}*30 = 10 \\\\ \boxed{x = 10}\\\\ \frac{y}{ \frac{1}{2} } = 30 \\\\y = \frac{1}{2}*30 = 15 \\\\ \boxed{y = 15}\\\\ \frac{z}{ \frac{1}{5} } = 30 \\\\y = \frac{1}{5}*30 = 6 \\\\ \boxed{z = 6}$

Answer 2

A+B+c=31
K/3+K/2+K/5=31
10K+15K+6K=31x30
31K=930
k=930/31
K=30
k/3= 30/3=10
k/2= 30/2=15
k/5= 30/5=6
Resposta: letra C