Question

Ao balancear a seguinte equação de combustão, teremos os seguintes coeficientes estequiométricos: C3H6 + O2 ----> CO2 + H2O *

Answer 1

$\large\boxed{\begin{array}{l}\underbrace{\rm C_3H_{16}}_{\rm a}+\underbrace{\rm O_2}_{\rm b}\longrightarrow\underbrace{\rm CO_2}_{\rm c}+\underbrace{\rm H_2O}_{\rm d}\\\begin{cases}\rm 3a=c\cdot 2\longrightarrow 6a=2c\\\rm 16a=2d\div2\longrightarrow 8a=d\\\rm 2b=2c+d\longrightarrow 2b=6a+8a\end{cases}\\\rm 2b=14a\\\rm b=\dfrac{14a}{2}\\\\\rm b=7a~~c=3a~~d=8a\\\sf adote\,a=1(elemento\,neutro)\\\rm b=7~~c=3~~d=8\end{array}}$

$\large\boxed{\begin{array}{l}\underline{\sf equac_{\!\!,}\tilde ao\,balanceada\!:}\\\rm C_3H_{16}+\bf{7} \rm O_2\longrightarrow\bf{3}\rm CO_2+\bf{8}\rm H_2O\end{array}}$