Question

analise combinatória (n+1)!=6

Answer 1

Olá!

$\\ \mathsf{(n + 1)! = 6} \\\\ \mathsf{(n + 1)! = 3 \cdot 2 \cdot 1} \\\\ \mathsf{(n + 1)! = 3!} \\\\ \mathsf{n + 1 = 3} \\\\ \boxed{\mathsf{n = 2}}$