Question

Analisando a equação dada. Diga quais suas raízes,(utilizar Bhaskara). x² + 5x = 0​

Answer 1

$\sf x^2+5x=0\\\\\\\sf \displaystyle x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}\\\\\\\sf \sqrt{5^2-4\cdot \:1\cdot \:0}\\\\\\\sf =\sqrt{5^2-0}\\\\\\\sf =\sqrt{5^2}\\\\\\\sf =5\\\\\\\\\ \sf x_1=\frac{-5+5}{2\cdot \:1},\:x_2=\frac{-5-5}{2\cdot \:1}\\\\\\\\\sf \frac{-5+5}{2\cdot \:1}\\\\\\\sf =\frac{0}{2\cdot \:1}\\\\\\\sf =\frac{0}{2}\\\\\\\sf x=0\\\\\\\\\sf \frac{-5-5}{2\cdot \:1}\\\\\\\sf =\frac{-10}{2\cdot \:1}$

$\sf \displaystyle =-\frac{10}{2}\\\\\\\sf x=-5$

$\to\boxed{\sf x=0}\\\to\boxed{\sf x=-5}$

Answer 2

Resposta:

oi boa noite tudo bem

Explicação passo-a-passo:

$x = 0 \\ x = - 5$