Question

Alta pontuação para resolver essas inequações

a)10.(3x+5)-20>=5.(2x-3)+30

b)25.(2x+3x)-40<=15.(4x+5)-50

c)60(3x-2x)>=30.(x+10x)+200

d)50(5x+3x)>=40.(2x+4x)+100

Answer 1

a)10.(3x+5)-20>=5.(2x-3)+30
30x + 50 -20>= 10x -15 + 30
30x-10x  >= + 15 - 50 + 20
20x >= - 15
x >= - 15/20
x> = -3/4

b)25.(2x+3x)-40<=15.(4x+5)-50
50x + 75x - 40 =< 60x + 75 - 50
125x - 40 =< 60x + 25
65x =< + 65
x =< +1

c)60(3x-2x)>=30.(x+10x)+200
180x - 120x >= 30x + 300x + 200
60x >= 330x + 220
- 270 x >= + 220 * (-1)
270x =< -220
27x =< -22
x =< -22/27

d)50(5x+3x)>=40.(2x+4x)+100
50*8x >= 40*6x + 100
400x >= 240x + 100
160 x >= 100
x >= 100/160
x >= 10/16
x>= 5/8

Answer 2

A) 30x+50-20>=10x-15+30
       20x>=-15
           x>=-3/4
B)50x +75x-40<= 60x+75-50
       65x<=65
             x<=1
C) 60x>=330x+200
          -270x>=200   .(-1)
               x<=-200/270
D) 400x>= 240x+100
          160x>=100
                x>= 100/160
                x>=20/32