Question

Algum gênio pra me ajudar?

Answer 1

Bom, se sabe que: Sen=CO/Hip Cos= CA/Hip & Tg= CO/CA

Assim:

a) SenC= 12/13
cosB= 12/13
tgB= 5/12

b) SenB=√2/√3
CosB=1/√3
tgC= 1/√2

c) SenB= 5/5√2 = 1/√2
CosB= 5/5√2 = 1/√2
TgC= 5/5=1

d) senX= 8/4√5= 4/√5
cosZ= 8/4√5= 4/√5
tgX= 8/4=2

e) SenO= 16/20= 4/5
cosP= 16/20= 4/5
tgP= 12/16= 3/4

f) SenR= 1,6/2= 0,8
CosT= 1,6/2= 0,8
tgT= 1,2/1,6= 0,3/0,4 OU 3/4(Simplificando)