Question

alguém?
${ \times }^{2} - 10x + 25 = 0$

Answer 1

delta=(-10x-10)-4.1.25
delta=100-100
delta=0
X=-b+-Raiz de delta/2.a
X=10+-0/2
X1=10/2=5
X2=10/2=5

Answer 2

x² - 10x + 25 = 0

a = 1
b= - 10
c = 25

Δ = b² -4 .a . c
Δ = (-10)² -4 . 1 . 25
Δ = 100 -4 . 25
Δ = 100 - 100
Δ = 0

$\mathtt{\dfrac{-b +- \sqrt{\Delta }}{2~~.~a} ~~=~~ \dfrac{- (-10) +-\sqrt{0}}{2~. ~1}~~=~~ \dfrac{10+-0}{2}} \\ \\ \\ \mathtt{\dfrac{10}{2}~~=~~5}$

Resposta: 5

Δ = 0 , só admite uma solução