Question

Alguém saberia responder ? Grato.

Answer 1

Eu sei:
Veja:

$\frac{2^{2007}+2^{2005}}{2^{2006}+2^{2004}}.2006=\\ \\ \frac{2^3.2^{2004}+2.2^{2004}}{2^2.2^{2004}+2^{2004}}.2006=\\ \\ \frac{(2^3+2)2^{2004}}{(2^2+1)2^{2004}}.2006\\ \\ \frac{10}{5}.2006=\\ \\ 2.2006=4012\\ \\ \boxed{Logo: 4+0+1+2=7}$