Question

Alguém saberia responder essa?!

Answer 1

Olá,

Resposta:

Sen de 30° = $\frac{1}{2}$

Sen de 45° = $\frac{\sqrt{2} }{2}$

Sen de 60° = $\frac{\sqrt{3} }{2}$

Cos de 30° = $\frac{\sqrt{3} }{2}$

Cos de 45° = $\frac{\sqrt{2} }{2}$

Cos de 60° = $\frac{1}{2}$

Tg de 30° = $\frac{\sqrt{3} }{3}$

Tg de 45° = 1

Tg de 60° = $\sqrt{3}$

Espero ter ajudado!

Answer 2

sen45° = $\frac{\sqrt{2}}{2}$

sen30° = $\frac{1}{2\\}$

sen60° = $\frac{\sqrt{3}}{2\\}$

cos45° = $\frac{\sqrt{2\\}}{2}$

cos30° = $\frac{\sqrt{3}}{2}$

cos60° = $\frac{1}{2}$

tan45° = 1

tan30° = $\frac{\sqrt{3}}{3}$

tan60° = $\sqrt{3\\}$