Question

alguém saber Responder essas questão aqui ?​

Answer 1

Resposta:

$a)7^{2} = 7.7=49$

$b)9^{o} =1$

$c)-10^{6} =10.10.10.10.10.10=-1000000$

$d)(-10)^{6} =(-10).(-10).(-10).(-10).(-10).(-10)=1000000$

$e)(-3)^{2}=(-3).(-3) = 9$

$f)(-3)^{3}= (-3).(-3).(-3)= -27$

$g)(-3)^{4}= (-3).(-3).(-3).(-3)= 81$

$h)(-3,4)^{4} =(-3,4).(-3,4).(-3,4).(-3,4)=133,6336$

$i)(-\frac{3}{2})^{2} =(-\frac{3}{2}).(-\frac{3}{2})=\frac{9}4}$

$j)(-\frac{3}{4})^{3} =(-\frac{3}{4}).(-\frac{3}{4}).(-\frac{3}{4})= -\frac{27}{64}$

$k)(1,9)^{2} =(1,9).(1,9)=3,61$

$l)20^{-1} = \frac{1}{20}^{1} =\frac{1}{20}$

$m)(-6)^{-1} =\frac{1}{6}^{1} =\frac{1}{6}$

$n)11^{-2} =\frac{1}{11}^{2} = \frac{1}{11}.\frac{1}{11} = \frac{1}{121}$

$o)2^{-6} =\frac{ 1}{2}^{6} = \frac{ 1}{2}.\frac{ 1}{2}.\frac{ 1}{2}.\frac{ 1}{2}.\frac{ 1}{2}.\frac{ 1}{2}. = \frac{1}{64}$

$p)(\frac{2}{3})^{-3} = \frac{3}{2} ^{3}= \frac{3}{2} .\frac{3}{2} \frac{3}{2} = \frac{27}{8}$

$q)(\frac{1}{3})^{-4} =3^{4}=3.3.3.3=81$

$r)(\frac{4}{3})^{-2} =\frac{3}{4} ^{2} =\frac{3}{4}.\frac{3}{4}=\frac{9}{16}$