Matemática, perguntado por carolaine42, 1 ano atrás

alguem sabe
x²+6x-15

Soluções para a tarefa

Respondido por LuanaSC8
0
 x^{2} +6x-15=0\\\\ a=1~;~b=6~;~c=-15\\\\\\ \Delta=b^2-4ac\to  \Delta=6^2-4.1.(-15)\to  \Delta=36+60\to \boxed{ \Delta=96}\\\\ x' \neq x''\\\\\\ x= \dfrac{-b\pm  \sqrt{ \Delta} }{2a} \to~~ x= \dfrac{-6\pm  \sqrt{96} }{2.1} \to~~  x= \dfrac{-6\pm  4\sqrt{ 6} }{2} \to~~\\\\\\ x'= \dfrac{-6+  4\sqrt{ 6} }{2} \to~~ \boxed{x'= -3+ 2\sqrt{ 6}}\\\\\\ x''= \dfrac{-6-  4\sqrt{ 6} }{2} \to~~ \boxed{x''= -3- 2\sqrt{ 6}}\\\\\\\\ \large\boxed{S= \{-3- 2\sqrt{ 6}~~;~~-3+2\sqrt{ 6}\}}
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