Question

Alguem sabe resolver o exercicio anexo.

Answer 1

Explicação passo-a-passo:

$\frac{(n-2)!(n-1)}{2n!} =\frac{1}{12} \\\\\frac{(n-2)!(n-1)}{2(n)(n-1)(n-2)!} =\frac{1}{12} \\\\\frac{1}{2n} =\frac{1}{12} \\\\2n=12\\n= 12/2\\n=6$

Bons estudos!