Question

Alguem sabe resolver essa conta X2 - 49 - 0

Answer 1

x^2-49=0
delta=b^2-4ac
delta=0^2-4.1.(-49)
delta=0+196
delta=196
x=-b-/+ raiz de delta/2a
x=-0-14/2.1
x=-14/2
x=-7
x=-0+14/2.1
x=14/2
x=7

Answer 2

$x^{2}-49=0 // a=1, c=-49$ ⇒
Δ=0²-4.1.(-49)
Δ=196

x'= $\frac{ \sqrt{196} }{2} = \frac{14}{2} = 7$
x''= $\frac{- \sqrt{196} }{2} = \frac{-14}{2} = -7$