Question

Alguem sabe resolver

Answer 1

Resposta:

1)

2*A+3*B= $\left[\begin{array}{ccc}-19&-20&33\\28&23&27\\32&27&28\end{array}\right]$

3*A-2*C= $\left[\begin{array}{ccc}-1&0&17\\-24&1&16\\8&-2&10\end{array}\right]$

2)

A= $\left[\begin{array}{ccc}0&-3\\1&-2\\2&-1\end{array}\right]$

Explicação passo-a-passo:

2*A=$\left[\begin{array}{ccc}2&4&6\\-8&5&12\\8&6&16\end{array}\right]$

3*B=$\left[\begin{array}{ccc}-21&-24&27\\36&18&15\\24&-21&12\end{array}\right]$

2*A+3*B=$\left[\begin{array}{ccc}2+(-21)&4+(-24)&6+27\\36+(-8)&5+18&12+15\\8+24&6+21&16+12\end{array}\right] ->\left[\begin{array}{ccc}-19&-20&33\\28&23&27\\32&27&28\end{array}\right]$

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3*A= $\left[\begin{array}{ccc}3&6&9\\-12&15&18\\12&18&24\end{array}\right]$

2*C= $\left[\begin{array}{ccc}4&6&-8\\12&14&2\\4&16&14\end{array}\right]$

3*A-2*C= $\left[\begin{array}{ccc}3-4&6-6&9-(-8)\\-12-12&15-(+14)&18-2\\12-4&16-18&24-14\end{array}\right] -> \left[\begin{array}{ccc}-1&0&17\\-24&1&16\\8&-2&10\end{array}\right]$

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A=$\left[\begin{array}{cc}a_{11}&a_{21}\\a_{21}&a_{22}\\a_{31}&a_{32}\end{array}\right] ->\left[\begin{array}{ccc}0&-3\\1&-2\\2&-1\end{array}\right]$