Question

Alguém sabe?pfvr?????

Answer 1

$log_{_{\sqrt[5]{16}}} \; \frac{1}{8}=x\\\\\frac{1}{8}=\sqrt[5]{16}^x\\\\\frac{1}{2^3}=\sqrt[5]{2^4}^x\\\\\left(2^3\right)^{-1}=2^{\left(\frac{4}{5}\right)^x}\\\\\left(2\right)^{-3}=2^{\frac{4}{5}x}\\\\-3=\frac{4}{5}x\\\\x = -\frac{15}{4}$