Question

alguem sabe fazer estas contas

Answer 1

Explicação passo-a-passo:

1)

a) $\sf \dfrac{5}{3}+\dfrac{7}{3}=\dfrac{5+7}{3}=\dfrac{12}{3}=\red{4}$

b) $\sf \dfrac{4}{5}-\dfrac{1}{5}+\dfrac{2}{5}=\dfrac{4-1+2}{5}=\dfrac{5}{5}=\red{1}$

c) $\sf \dfrac{1}{6}+\dfrac{3}{6}-\dfrac{7}{6}=\dfrac{1+3-7}{6}=\dfrac{-3}{6}=\red{-\dfrac{1}{2}}$

d) $\sf \dfrac{3}{4}+\dfrac{1}{4}+\dfrac{7}{4}=\dfrac{3+1+7}{4}=\red{\dfrac{11}{4}}$

e) $\sf -\dfrac{1}{9}-\dfrac{3}{9}-\dfrac{5}{9}=\dfrac{-1-3-5}{9}=\dfrac{-9}{9}=\red{-1}$

2)

a) $\sf -\dfrac{2}{3}-\dfrac{1}{4}-\dfrac{2}{6}=\dfrac{-8-3-4}{12}=\dfrac{-15}{12}=\red{-\dfrac{5}{4}}$

b) $\sf \dfrac{1}{4}-\dfrac{2}{3}=\dfrac{3-8}{12}=\red{-\dfrac{5}{12}}$

c) $\sf -\dfrac{2}{5}+\dfrac{1}{10}+\dfrac{7}{10}=\dfrac{-4+1+7}{10}=\dfrac{4}{10}=\red{\dfrac{2}{5}}$

d) $\sf \dfrac{3}{5}-\dfrac{2}{3}-\dfrac{1}{2}=\dfrac{18-20-15}{30}=\red{-\dfrac{17}{30}}$

e) $\sf \dfrac{6}{5}-\dfrac{1}{10}+\dfrac{3}{10}=\dfrac{12-1+3}{10}=\dfrac{14}{10}=\red{\dfrac{7}{5}}$