Matemática, perguntado por mariahjs, 1 ano atrás

alguém sabe fazer essas frações e simplificar elas?​

Anexos:

Soluções para a tarefa

Respondido por Usuário anônimo
2

Explicação passo-a-passo:

a) A=\dfrac{12}{20}+\dfrac{3}{5}

Veja que \dfrac{12\div4}{20\div4}=\dfrac{3}{5}

Então:

A=\dfrac{3}{5}+\dfrac{3}{5}

A=\dfrac{3+3}{5}

A=\dfrac{6}{5}

b) B=\dfrac{11}{20}-\dfrac{25}{52}

mmc(20,52)=260

B=\dfrac{11\cdot13-25\cdot5}{260}

B=\dfrac{143-125}{260}

B=\dfrac{18}{260}

B=\dfrac{9}{130}

c) C=\dfrac{125}{150}\cdot\dfrac{5}{20}

Note que:

\dfrac{125\div25}{150\div25}=\dfrac{5}{6}

\dfrac{5\div5}{20\div5}=\dfrac{1}{4}

Então:

C=\dfrac{5}{6}\cdot\dfrac{1}{4}

C=\dfrac{5\cdot1}{6\cdot4}

C=\dfrac{5}{24}

d) D=\dfrac{10}{20}\div\dfrac{23}{50}

D=\dfrac{1}{2}\div\dfrac{23}{50}

D=\dfrac{1}{2}\cdot\dfrac{50}{23}

D=\dfrac{1\cdot50}{2\cdot23}

D=\dfrac{50}{46}

D=\dfrac{25}{23}

e) E=\dfrac{1}{3}+\dfrac{2}{6}

Veja que \dfrac{2\div2}{6\div2}=\dfrac{1}{3}

E=\dfrac{1}{3}+\dfrac{1}{3}

E=\dfrac{2}{3}

f) F=\dfrac{7}{17}-\dfrac{10}{5}

F=\dfrac{7}{17}-2

F=\dfrac{7-2\cdot17}{17}

F=\dfrac{7-34}{17}

F=\dfrac{-27}{17}

g) G=\dfrac{10}{8}\cdot\dfrac{7}{15}

G=\dfrac{10\cdot7}{8\cdot15}

G=\dfrac{70}{120}

G=\dfrac{7}{12}

h) H=\dfrac{121}{203}\div\dfrac{33}{54}

Veja que \dfrac{33\div3}{54\div3}=\dfrac{11}{18}

H=\dfrac{121}{203}\div\dfrac{11}{18}

H=\dfrac{121}{203}\cdot\dfrac{18}{11}

H=\dfrac{11\cdot18}{203}

H=\dfrac{198}{203}

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