alguém sabe esta questão
Anexos:
Usuário anônimo:
O número 12 esta entre parenteses?
1728
Oi Gisinha! É uma divisão.
ops, desculpe , errei rsrs, obrigada
Fica tranquila, erros acontecem.
Soluções para a tarefa
Respondido por
2
Boa noite!
Solução!
![\dfrac{12^{ 2^{3} }}{ \dfrac{12^{3} }{12} } \times(12^{2^{0} )}\\\\\\\
12^{ 2^{3} }\times12^{-1}\times12^{-3} \times(12^{2^{0} )}\\\\\\\
12^{ 8 }\times12^{-1}\times12^{-3} \times(12^{2^{0} )}\\\\\\\
12^{ 4 } \times(12^1}\\\\\\\
12^{4+1}\\\\\
12^{5} =248832](https://tex.z-dn.net/?f=+%5Cdfrac%7B12%5E%7B+2%5E%7B3%7D+%7D%7D%7B+%5Cdfrac%7B12%5E%7B3%7D+%7D%7B12%7D+%7D+%5Ctimes%2812%5E%7B2%5E%7B0%7D+%29%7D%5C%5C%5C%5C%5C%5C%5C+%0A12%5E%7B+2%5E%7B3%7D+%7D%5Ctimes12%5E%7B-1%7D%5Ctimes12%5E%7B-3%7D+%5Ctimes%2812%5E%7B2%5E%7B0%7D+%29%7D%5C%5C%5C%5C%5C%5C%5C%0A+12%5E%7B+8+%7D%5Ctimes12%5E%7B-1%7D%5Ctimes12%5E%7B-3%7D+%5Ctimes%2812%5E%7B2%5E%7B0%7D+%29%7D%5C%5C%5C%5C%5C%5C%5C%0A++12%5E%7B+4+%7D+%5Ctimes%2812%5E1%7D%5C%5C%5C%5C%5C%5C%5C%0A12%5E%7B4%2B1%7D%5C%5C%5C%5C%5C%0A12%5E%7B5%7D+%3D248832+%0A++++ "\dfrac{12^{ 2^{3} }}{ \dfrac{12^{3} }{12} } \times(12^{2^{0} )}\\\\\\\
12^{ 2^{3} }\times12^{-1}\times12^{-3} \times(12^{2^{0} )}\\\\\\\
12^{ 8 }\times12^{-1}\times12^{-3} \times(12^{2^{0} )}\\\\\\\
12^{ 4 } \times(12^1}\\\\\\\
12^{4+1}\\\\\
12^{5} =248832")
Boa noite!
Bons estudos!
Solução!
Boa noite!
Bons estudos!
muito obrigado
Dê nada!
Perguntas interessantes