Question

ALGUÉM SABE COMO RESOLVE????

Answer 1

f'(x)= 4/3(x^2-6)^1/3*2x-27(x/3+5)^-2*1/3+senxe^cosx

f'(x)=8/3*(x-6)^1/3 - 9/(x/3 + 5)^2 + senxe^cosx