Question

alguém sabe calcular a derivada de

y=x³+1/x-1

Answer 1

$\frac{d}{dx} \frac{x^3+1}{x-1} = \\ \\ = \frac{ \frac{d}{dx}(x^3+1)(X-1)- \frac{d}{dx} (x-1)(x^3+1) }{(x-1)^2} = \frac{3x^2(x-1)-1(x^3+1)}{(x-1)^2} = \\ \\ = \frac{3x^3-3x^2-x^3-1}{(x-1)^2} = \frac{2x^3-3x^2-1}{(x-1)^2}$