Question

alguém sabe cacular essa equação:
$\sqrt[3]{ 2^{28} + 2^{30} }$÷∛10

Answer 1

$\large{\frac{ \sqrt[3]{(2^{28}+2^{30)}}}{ \sqrt[3]{10}}$

$\large{\frac{ \sqrt[3]{(2^{27}(2^1+2^{3})}}{ \sqrt[3]{10} }$

$\large{\frac{ \sqrt[3]{2^{27}(10)}}{ \sqrt[3]{10} }$

$\frac{2^9( \sqrt[3]{10})}{ \sqrt[3]{10}}\\ \\ \large{\boxed{2^9}$