alguém sabe a resposta dessa?
Anexos:
Soluções para a tarefa
Respondido por
1
1.1.3+0.3.1+(-1).x.x-(-1).1.1-1.3.x-0.x.3=0
3+0-x²+1-3x-0=0
-x²-3x+4=0
encontrando as raízes
x=-4 e x=1
item d
3+0-x²+1-3x-0=0
-x²-3x+4=0
encontrando as raízes
x=-4 e x=1
item d
Respondido por
1
Boa tarde Luis!
Solução!
Vamos calcular o determinante,para encontramos uma equação do 2ºgrau.
![\begin{vmatrix}
1 & 0&-1 \\
x & 1&3 \\
1&x&3
\end{vmatrix}=0\\\\\\\\
\begin{vmatrix}
1 & 0&-1&1&0\\
x & 1&3&x&1 \\
1&x&3&1&x
\end{vmatrix}=0\\\\\\\\\\\\\\
Vamos~~multiplicar~~as~~diagonais~~principais\\\\\\es~~as~~secundarias.Lembrando~~que~~as~~secundarias\\\\\\\
tem~~sinais~~negativos.](https://tex.z-dn.net/?f=+%5Cbegin%7Bvmatrix%7D+%0A++1+%26amp%3B+0%26amp%3B-1+%5C%5C+%0A++x+%26amp%3B+1%26amp%3B3+%5C%5C%0A1%26amp%3Bx%26amp%3B3%0A++%5Cend%7Bvmatrix%7D%3D0%5C%5C%5C%5C%5C%5C%5C%5C%0A+%5Cbegin%7Bvmatrix%7D+%0A++1+%26amp%3B+0%26amp%3B-1%26amp%3B1%26amp%3B0%5C%5C+%0A++x+%26amp%3B+1%26amp%3B3%26amp%3Bx%26amp%3B1+%5C%5C%0A1%26amp%3Bx%26amp%3B3%26amp%3B1%26amp%3Bx%0A++%5Cend%7Bvmatrix%7D%3D0%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0AVamos%7E%7Emultiplicar%7E%7Eas%7E%7Ediagonais%7E%7Eprincipais%5C%5C%5C%5C%5C%5Ces%7E%7Eas%7E%7Esecundarias.Lembrando%7E%7Eque%7E%7Eas%7E%7Esecundarias%5C%5C%5C%5C%5C%5C%5C%0Atem%7E%7Esinais%7E%7Enegativos.%0A "\begin{vmatrix}
1 & 0&-1 \\
x & 1&3 \\
1&x&3
\end{vmatrix}=0\\\\\\\\
\begin{vmatrix}
1 & 0&-1&1&0\\
x & 1&3&x&1 \\
1&x&3&1&x
\end{vmatrix}=0\\\\\\\\\\\\\\
Vamos~~multiplicar~~as~~diagonais~~principais\\\\\\es~~as~~secundarias.Lembrando~~que~~as~~secundarias\\\\\\\
tem~~sinais~~negativos.")
![(3+0- x^{2} )+(1-3x+0)=0\\\\\\
- x^{2} -3x+4=0\\\\\
x^{2} +3x-4=0](https://tex.z-dn.net/?f=%283%2B0-+x%5E%7B2%7D+%29%2B%281-3x%2B0%29%3D0%5C%5C%5C%5C%5C%5C%0A-+x%5E%7B2%7D+-3x%2B4%3D0%5C%5C%5C%5C%5C%0A+x%5E%7B2%7D+%2B3x-4%3D0 "(3+0- x^{2} )+(1-3x+0)=0\\\\\\
- x^{2} -3x+4=0\\\\\
x^{2} +3x-4=0")
Aplicando a formula de Bhaskara!
![x= \dfrac{-3\pm \sqrt{3^{2}-4.1.-4 } }{2.1}\\\\\\\\\\\
x= \dfrac{-3\pm \sqrt{9+16 } }{2}\\\\\\\\\\\
x= \dfrac{-3\pm \sqrt{25 } }{2}\\\\\\\\\\\
x= \dfrac{-3\pm 5}{2}\\\\\\\\\\\
Raizes!\\\\\\
x_{1}= \dfrac{-3+5}{2}= \dfrac{2}{2}=1\\\\\\\\\
x_{2}= \dfrac{-3-5}{2}= \dfrac{-8}{2}=-4\\\\\\\\\
S=\{-4,1\}](https://tex.z-dn.net/?f=x%3D+%5Cdfrac%7B-3%5Cpm+%5Csqrt%7B3%5E%7B2%7D-4.1.-4+%7D+%7D%7B2.1%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C+%0Ax%3D+%5Cdfrac%7B-3%5Cpm+%5Csqrt%7B9%2B16+%7D+%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C+%0Ax%3D+%5Cdfrac%7B-3%5Cpm+%5Csqrt%7B25+%7D+%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C+%0Ax%3D+%5Cdfrac%7B-3%5Cpm+5%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0ARaizes%21%5C%5C%5C%5C%5C%5C%0A+x_%7B1%7D%3D+%5Cdfrac%7B-3%2B5%7D%7B2%7D%3D+%5Cdfrac%7B2%7D%7B2%7D%3D1%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A+x_%7B2%7D%3D+%5Cdfrac%7B-3-5%7D%7B2%7D%3D+%5Cdfrac%7B-8%7D%7B2%7D%3D-4%5C%5C%5C%5C%5C%5C%5C%5C%5C%0AS%3D%5C%7B-4%2C1%5C%7D+++ "x= \dfrac{-3\pm \sqrt{3^{2}-4.1.-4 } }{2.1}\\\\\\\\\\\
x= \dfrac{-3\pm \sqrt{9+16 } }{2}\\\\\\\\\\\
x= \dfrac{-3\pm \sqrt{25 } }{2}\\\\\\\\\\\
x= \dfrac{-3\pm 5}{2}\\\\\\\\\\\
Raizes!\\\\\\
x_{1}= \dfrac{-3+5}{2}= \dfrac{2}{2}=1\\\\\\\\\
x_{2}= \dfrac{-3-5}{2}= \dfrac{-8}{2}=-4\\\\\\\\\
S=\{-4,1\}")
Boa tarde!
Bons estudos!
Solução!
Vamos calcular o determinante,para encontramos uma equação do 2ºgrau.
Aplicando a formula de Bhaskara!
Boa tarde!
Bons estudos!
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