Question

Alguém sabe a resolução, pfv? Estou tentando faz tempo e sempre empaco com
4^6 . 6^6 / 3^6 . 2^6 = 2n

Answer 1

$\displaystyle \sf \frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5} \cdot \frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2^n \\\\\\ \frac{4\cdot 4^5 }{3\cdot 3^5 }\cdot \frac{6\cdot 6^5}{2\cdot 2^5 }=2^n \\\\\\ \frac{4^{(1+5)}}{3^{(1+5)}} \cdot \frac{6^{(1+5)}}{2^{(1+5)}} = 2^n \\\\\\ \frac{4^6 }{3^6} \cdot \frac{6^6}{2^6} = 2 ^n \\\\\\ \left(\frac{4}{3} \cdot \frac{6}{2} \right ) ^{6} = 2^n \\\\\\ \left(2\cdot 2 \right ) ^{6} = 2^n \\\\ \left(2^2\right)^{6} = 2^n \\\\ 2^{2\cdot 6} = 2 ^n \\\\ 2^{12} = 2^n$

$\huge\boxed{\sf n = 12}\checkmark$

Answer 2

Batata =x-y de uma forma que você poderia me dizer o quanto você eururrurjdnjj