Question

Alguém?????????? Sabe???

Answer 1

h)
$\sqrt{2} ^{x} = 8 \\ \sqrt{2} ^{x} = 2^{3} \\ \sqrt{2} ^{2*x} = 2^{2*3} \\ 2 ^{x} = 2^{6} \\ x=6$



i)
$\sqrt[4]{3} ^{x} = \sqrt[3]{9} \\ \\ 3 ^{ \frac{x}{4} } = \sqrt[3]{3}^{2} \\ \\ 3 ^{ \frac{x}{4} }= 3^{\frac{2}{3} } \\ \\ \frac{x}{4} = \frac{2}{3} \\ \\ 3x=2*4 \\ 3x=8 \\ x= \frac{8}{3}$

j) 
$\sqrt[5]{4}^{x} = \frac{1}{ \sqrt{8} } \\ \\ 4^{ \frac{x}{5} } = 8^{ \frac{-1}{2} } \\ \\ 2^{2 \frac{x}{5} } = 2^{3 \frac{-1}{2} } \\ \\ \frac{2x}{5} = \frac{-3}{2} \\ \\ 2(2x)=5*-3 \\ \\ 4x=-15 \\ \\ x=-15/4$