Question

Alguém responde isso pra mim?

Answer 1

$m^4- \frac{1}{3} a.m^2+ \frac{2}{5}a.m^2- \frac{2}{15} a^2 = - m^4+ \frac{2}{5}a.m^2- \frac{1}{3}a.m^2- \frac{2}{15}a^2 = - m^4 + \frac{3.(2am^2)}{15} - \frac{5.(a.m^2)}{15} - \frac{2a^2}{15} - m^4+ \frac{6am^2}{15} - \frac{5am^2}{15} - \frac{2a^2}{15} - m^4 + \frac{am^2}{15} - \frac{2a^2}{15}$