ALGUEM RESPONDE ESSAS QUESTÕES DE BHASKARA PLEASE :)
Soluções para a tarefa
Explicação passo-a-passo:
x² - 4x + 9 = 0
a= 1; b = -4; c = 9
D = -4² - 4 . 1 . 9
D = 16 - 36
D = -20
25x² - 20x + 4 = 0
a= 25; b = -20; c = 4
D = -20² - 4 . 25 . 4
D = 400 - 400
D = 0
x' = -(-20) + 0
2 . 25
x' = 20 + 0
50
x' = 20
50
x' = 2/5
x" = -(-20) - 0
2 . 25
x" = 20 - 0
50
x'' = 20
50
x'' = 2/5
x² + 2x - 15 = 0
a= 1; b = 2; c = -15
D = 2² - 4 . 1 . (-15)
D = 4 + 60
D = 64
x' = -2 + 8
2 . 1
x' = -2 + 8
2
x' = 6
2
x' = 3
x" = -2 - 8
2 . 1
x" = -2 - 8
2
x'' = -10
2
x'' = -5
x² + 3x + 2 = 0
a= 1; b = 3; c = 2
D = 3² - 4 . 1 . 2
D = 9 - 8
D = 1
x' = -3 + 1
2 . 1
x' = -3 + 1
2
x' = -2
2
x' = -1
x" = -3 - 1
2 . 1
x" = -3 - 1
2
x'' = -4
2
x'' = -2
x² + x - 12 = 0
a= 1; b = 1; c = -12
D = 1² - 4 . 1 . (-12)
D = 1 + 48
D = 49
x' = -1 + 7
2 . 1
x' = -1 + 7
2
x' = 6
2
x' = 3
x" = -1 - 7
2 . 1
x" = -1 - 7
2
x'' = -8
2
x'' = -4
x² - 2x + 1 = 0
a= 1; b = -2; c = 1
D = -2² - 4 . 1 . 1
D = 4 - 4
D = 0
x' = -(-2) + 0
2 . 1
x' = 2 + 0
2
x' = 2
2
x' = 1
x" = -(-2) - 0
2 . 1
x" = 2 - 0
2
x'' = 2
2
x'' = 1
x² + 6x + 9 = 0
a= 1; b = 6; c = 9
D = 6² - 4 . 1 . 9
D = 36 - 36
D = 0
x' = -6 + 0
2 . 1
x' = -6 + 0
2
x' = -6
2
x' = -3
x" = -6 - 0
2 . 1
x" = -6 - 0
2
x'' = -6
2
x'' = -3
4 + x² - 4x = x
x² - 5x + 4 = 0
a= 1; b = -5; c = 4
D = -5² - 4 . 1 . 4
D = 25 - 16
D = 9
x' = -(-5) + 3
2 . 1
x' = 5 + 3
2
x' = 8
2
x' = 4
x" = -(-5) - 3
2 . 1
x" = 5 - 3
2
x'' = 2
2
x'' = 1