Question

alguém resolver??????​

Answer 1

$f(x)=3^x$

$f(-2)=3^-^2\\f(-2)=\frac{1}{9}$

$f(-1)=3^-^1\\f(-1)=\frac{1}{3}$

$f(0)=3^0\\f(0)=1$

$f(1)=3^1\\f(1)=3$

$f(2)=3^2\\f(2)=9$

$A=(-2,\frac{1}{9})\\B=(-1,\frac{1}{3} )\\C=(0,1)\\D=(1,3)\\E=(2,9)$