Question

alguém resolve pra mim por favor !

Answer 1

$[tex] \frac{x^2}{2}+ \frac{3x}{5}= \frac{30+x}{10} \\ 5x^2+6x=x+30\\ \frac{10x^2}{2} + \frac{10*3}{5} = \frac{10(30+x)}{10} \\ 5x^2+ \frac{30x}{5} =30+x\\ 5x^2+5x-30=0 \\ 5x^2+6x+-x-30=x+30+-x-30 \\ \frac{x^2}{2} + \frac{3x}{5} = \frac{30+x}{10} \\ x-2=0-ou-x+3=0 \\ x=2-ou-x=3$[/tex]

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